Timeline for Equidistribution Theorem: distance between solutions
Current License: CC BY-SA 3.0
10 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| S Dec 22, 2011 at 1:21 | vote | accept | Sasha | ||
| Dec 7, 2011 at 3:04 | answer | added | GH from MO | timeline score: 1 | |
| Dec 7, 2011 at 2:40 | vote | accept | Sasha | ||
| S Dec 22, 2011 at 1:21 | |||||
| Dec 7, 2011 at 2:40 | vote | accept | Sasha | ||
| Dec 7, 2011 at 2:40 | |||||
| Dec 7, 2011 at 2:38 | vote | accept | Sasha | ||
| Dec 7, 2011 at 2:40 | |||||
| Dec 7, 2011 at 1:15 | answer | added | john mangual | timeline score: 2 | |
| Dec 6, 2011 at 18:12 | answer | added | Alan Haynes | timeline score: 0 | |
| Dec 6, 2011 at 8:39 | comment | added | Vagabond | Try applying pigeonhole principle you should be able to get what you are looking for. Its also called Dirichlet's Box Principle. | |
| Dec 6, 2011 at 8:12 | answer | added | Asaf | timeline score: 2 | |
| Dec 6, 2011 at 7:58 | history | asked | Sasha | CC BY-SA 3.0 |