Timeline for Banach-Mazur applied to a Hilbert space
Current License: CC BY-SA 3.0
5 events
when toggle format | what | by | license | comment | |
---|---|---|---|---|---|
Dec 7, 2011 at 15:47 | vote | accept | Laurent Berger | ||
Dec 6, 2011 at 23:57 | comment | added | Bill Johnson | @ Laurent. Actually there is a deep explanation for that. If you think about $\ell_2$ as being the closed span $R$ of the Rademacher functions in $L_1$ (or a sequence of IID gaussians) and $T$ is an isomorphism from $R$ into $C[0,1/2]$ (considered as a subspace of $C[0,1]$ in the obvious way), then there is an extension of $T$ to an isomorphism from $L_1$ into $C[0,1]$. | |
Dec 6, 2011 at 17:06 | comment | added | Laurent Berger | For some reason, it's much easier to realize $\ell^1(R)$ as a subspace of $C^0([0;1],R)$. | |
Dec 6, 2011 at 17:05 | comment | added | Laurent Berger | Thank you! I was hoping for an easier answer, but of course now that I think about it, a sequence of functions which form a Hilbert basis really amounts to the coordinates of a continuous surjective map to the weak unit ball, so the answer is bound to be complicated. | |
Dec 5, 2011 at 20:40 | history | answered | Robert Israel | CC BY-SA 3.0 |