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Dec 31, 2011 at 23:02 history edited user16007 CC BY-SA 3.0
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Dec 31, 2011 at 22:50 comment added user16007 @Yemon Choi: I realized that I am only interested in the cube setting. FInite field setting seemed to be irrelevant. So I removed the finite field setting.
Dec 31, 2011 at 22:47 comment added Yemon Choi You seem to have made many minor edits in the last 24 hours. I suggest that this is not achieving anything, except bumping the question to the top of the queue. Perhaps you should stop and wait for a while?
Dec 31, 2011 at 22:43 history rollback user16007
Rollback to Revision 13
Dec 31, 2011 at 22:27 history edited user16007 CC BY-SA 3.0
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Dec 31, 2011 at 20:08 history edited user16007 CC BY-SA 3.0
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Dec 31, 2011 at 19:49 history edited user16007 CC BY-SA 3.0
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Dec 31, 2011 at 8:55 history edited user16007
edited tags
Dec 5, 2011 at 18:31 history edited user16007 CC BY-SA 3.0
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Dec 5, 2011 at 18:23 history edited user16007 CC BY-SA 3.0
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Dec 5, 2011 at 18:04 history edited user16007 CC BY-SA 3.0
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Dec 5, 2011 at 17:57 comment added user16007 @Mark Sapir: Updated the question. I think it may make more sense now.
Dec 5, 2011 at 17:56 comment added user16007 @Yemon Choi: Updated the question.
Dec 5, 2011 at 17:55 history edited user16007 CC BY-SA 3.0
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Dec 5, 2011 at 10:36 comment added Yemon Choi "What tools could be useful to study this problem" - what did you have in mind? Algorithms? Textbooks? Papers in Inventiones?
Dec 5, 2011 at 6:34 comment added user6976 Then it is not a field, right? A direct sum of fields has zero divisors.
Dec 5, 2011 at 6:33 comment added David Roberts @unknown - if you are not using the field structure, then just stick with it being a vector space, and call it such.
Dec 5, 2011 at 6:00 history rollback user16007
Rollback to Revision 3
Dec 5, 2011 at 5:59 history rollback user16007
Rollback to Revision 2
Dec 5, 2011 at 5:54 comment added user16007 @Mark Sapir: Actually I was thinking of the former one, since I do not know how I would define a tensor product in the former one non-trivially (I may be wrong on this but I meant the former one).
Dec 5, 2011 at 5:33 comment added user6976 I replaced $F_{3}^{n^i}$ which is not a field by $F_{3^{n^i}}$ which is a field. Hope this is what you meant.
Dec 5, 2011 at 5:32 history edited user6976 CC BY-SA 3.0
fixed LaTeX a little
Dec 5, 2011 at 5:27 history edited Angelo CC BY-SA 3.0
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Dec 5, 2011 at 4:50 history edited user16007 CC BY-SA 3.0
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Dec 5, 2011 at 4:44 history asked user16007 CC BY-SA 3.0