Timeline for Representing vertices of a cube using linear combination of tensor product of smaller cubes
Current License: CC BY-SA 3.0
25 events
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Dec 31, 2011 at 23:02 | history | edited | user16007 | CC BY-SA 3.0 |
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Dec 31, 2011 at 22:50 | comment | added | user16007 | @Yemon Choi: I realized that I am only interested in the cube setting. FInite field setting seemed to be irrelevant. So I removed the finite field setting. | |
Dec 31, 2011 at 22:47 | comment | added | Yemon Choi | You seem to have made many minor edits in the last 24 hours. I suggest that this is not achieving anything, except bumping the question to the top of the queue. Perhaps you should stop and wait for a while? | |
Dec 31, 2011 at 22:43 | history | rollback | user16007 |
Rollback to Revision 13
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Dec 31, 2011 at 22:27 | history | edited | user16007 | CC BY-SA 3.0 |
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Dec 31, 2011 at 20:08 | history | edited | user16007 | CC BY-SA 3.0 |
deleted 1118 characters in body; edited title; edited tags; Post Made Community Wiki
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Dec 31, 2011 at 19:49 | history | edited | user16007 | CC BY-SA 3.0 |
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Dec 31, 2011 at 8:55 | history | edited | user16007 |
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Dec 5, 2011 at 18:31 | history | edited | user16007 | CC BY-SA 3.0 |
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Dec 5, 2011 at 18:23 | history | edited | user16007 | CC BY-SA 3.0 |
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Dec 5, 2011 at 18:04 | history | edited | user16007 | CC BY-SA 3.0 |
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Dec 5, 2011 at 17:57 | comment | added | user16007 | @Mark Sapir: Updated the question. I think it may make more sense now. | |
Dec 5, 2011 at 17:56 | comment | added | user16007 | @Yemon Choi: Updated the question. | |
Dec 5, 2011 at 17:55 | history | edited | user16007 | CC BY-SA 3.0 |
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Dec 5, 2011 at 10:36 | comment | added | Yemon Choi | "What tools could be useful to study this problem" - what did you have in mind? Algorithms? Textbooks? Papers in Inventiones? | |
Dec 5, 2011 at 6:34 | comment | added | user6976 | Then it is not a field, right? A direct sum of fields has zero divisors. | |
Dec 5, 2011 at 6:33 | comment | added | David Roberts♦ | @unknown - if you are not using the field structure, then just stick with it being a vector space, and call it such. | |
Dec 5, 2011 at 6:00 | history | rollback | user16007 |
Rollback to Revision 3
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Dec 5, 2011 at 5:59 | history | rollback | user16007 |
Rollback to Revision 2
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Dec 5, 2011 at 5:54 | comment | added | user16007 | @Mark Sapir: Actually I was thinking of the former one, since I do not know how I would define a tensor product in the former one non-trivially (I may be wrong on this but I meant the former one). | |
Dec 5, 2011 at 5:33 | comment | added | user6976 | I replaced $F_{3}^{n^i}$ which is not a field by $F_{3^{n^i}}$ which is a field. Hope this is what you meant. | |
Dec 5, 2011 at 5:32 | history | edited | user6976 | CC BY-SA 3.0 |
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Dec 5, 2011 at 5:27 | history | edited | Angelo | CC BY-SA 3.0 |
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Dec 5, 2011 at 4:50 | history | edited | user16007 | CC BY-SA 3.0 |
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Dec 5, 2011 at 4:44 | history | asked | user16007 | CC BY-SA 3.0 |