Timeline for Uniform continuity and boundedness
Current License: CC BY-SA 3.0
6 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Dec 24, 2011 at 6:40 | comment | added | Toby Bartels | I assumed that "$I,[a,b]$" should be read as "$I \subseteq [a,b]$", rather than as "$I = [a,b]$". | |
| Dec 4, 2011 at 11:07 | comment | added | krje1980 | Oh, yeah. That's right! Ha ha. Thanks a lot :) | |
| Dec 4, 2011 at 10:52 | comment | added | Andrei MF | You wrote $[a,b]$, this is closed and bounded $\Rightarrow$ compact. | |
| Dec 4, 2011 at 10:51 | comment | added | Antoine Levitt | [a,b] is compact, end of story. | |
| Dec 4, 2011 at 9:54 | comment | added | krje1980 | Thanks. But in this case, we only know the set is bounded, not compact. | |
| Dec 4, 2011 at 9:34 | history | answered | Andrei MF | CC BY-SA 3.0 |