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Aug 1, 2021 at 8:38 comment added Stefan Kohl The second link appears to be broken again. -- Do you perhaps know a current one which works?
Dec 4, 2011 at 16:34 comment added Vitali Kapovitch @algori sorry about the second link. I just fixed it. please try now.
Dec 4, 2011 at 16:33 history edited Vitali Kapovitch CC BY-SA 3.0
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Dec 4, 2011 at 16:16 comment added algori Vitaly -- your first link requires a password and the second link seems broken (error 404). Could you perhaps give an alternative reference?
Dec 4, 2011 at 7:41 vote accept COhrt
Dec 4, 2011 at 4:42 comment added Tom Goodwillie $\mathbb R^\infty$ is smoothly isomorphic to $\mathbb S^\infty$. Who knew?
Dec 4, 2011 at 0:00 history edited Vitali Kapovitch CC BY-SA 3.0
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Dec 3, 2011 at 23:46 history edited Vitali Kapovitch CC BY-SA 3.0
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Dec 3, 2011 at 23:07 comment added Dylan Wilson +1 for a definitive, coherent, and nicely written answer. And I didn't know about that result for infinite-dimensional manifolds- very neat!
Dec 3, 2011 at 21:31 history edited Vitali Kapovitch CC BY-SA 3.0
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Dec 3, 2011 at 21:13 history edited Vitali Kapovitch CC BY-SA 3.0
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Dec 3, 2011 at 21:07 history edited Vitali Kapovitch CC BY-SA 3.0
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Dec 3, 2011 at 21:01 history answered Vitali Kapovitch CC BY-SA 3.0