Skip to main content
3 events
when toggle format what by license comment
Dec 1, 2011 at 17:49 comment added florian You are right of course. Sorry for this impreciseness. My question, however, remains the same.
Dec 1, 2011 at 16:24 comment added Mark Meckes Actually, Bernstein's theorem says that such a function is the Laplace transform of a finite measure on $(0,\infty)$, not necessarily of a function. For example, $f(x) = e^{-x}$ is the Laplace transform of a point mass.
Dec 1, 2011 at 15:57 history asked florian CC BY-SA 3.0