Timeline for Is every finitely generated idempotent ring singly generated as a two-sided ideal?
Current License: CC BY-SA 3.0
9 events
| when toggle format | what | by | license | comment | |
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| Dec 7, 2011 at 12:43 | comment | added | Andreas Thom | George Bergman has shown me a proof which works over every unital commutative ring; even commutativity is not necessary I think. | |
| Dec 2, 2011 at 21:50 | comment | added | user6976 | Ben: As I understood, $K$ is a field. | |
| Dec 2, 2011 at 18:59 | comment | added | Benjamin Steinberg | Mark, thanks. Does K have to be a field or does it work over the integral semigroup ring? I assume the latter. | |
| Dec 2, 2011 at 15:29 | history | edited | user6976 | CC BY-SA 3.0 |
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| Dec 1, 2011 at 15:29 | comment | added | user6976 | If Agata cannot do it, nobody can. I have sent her the example. | |
| Dec 1, 2011 at 13:52 | comment | added | Andreas Thom | Anyway, your example looks very interesting. | |
| Dec 1, 2011 at 13:45 | comment | added | Andreas Thom | Thanks. I asked Agata already, and she could not come up with an example. | |
| Dec 1, 2011 at 13:11 | history | edited | user6976 | CC BY-SA 3.0 |
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| Dec 1, 2011 at 13:03 | history | answered | user6976 | CC BY-SA 3.0 |