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Apr 13, 2017 at 12:58 history edited CommunityBot
replaced http://mathoverflow.net/ with https://mathoverflow.net/
Dec 3, 2011 at 4:18 comment added Stanley Yao Xiao Would the existence of a rational curve in a surface imply the existence of many rational solutions?
Nov 30, 2011 at 15:14 comment added Felipe Voloch But in weighted projective space what do you mean by a line? Just a rational curve?
Nov 30, 2011 at 14:58 comment added Stanley Yao Xiao Yes; I do mean a surface in weighted projective space.
Nov 30, 2011 at 14:58 history edited Stanley Yao Xiao CC BY-SA 3.0
added 31 characters in body
Nov 30, 2011 at 1:10 comment added Jason Starr You can consider it as a surface in a weighted projective space $\mathbb{P}(a,a,b,b)$ such that $a\text{deg}(f)$ equals $b\text{deg}(g)$ (and probably best to assume that $a$ and $b$ are relatively prime).
Nov 29, 2011 at 23:25 comment added Daniel Loughran Unless I am mistaken, one cannot view what you have written down ($f(x_1,x_2)=g(x_3,x_4)$) as a being a surface unless $f$ and $g$ are homogeneous of the same degree, and also in which case you need to consider the corresponding variety as being projective.
Nov 29, 2011 at 22:57 history asked Stanley Yao Xiao CC BY-SA 3.0