Timeline for Lie bracket of Invariant Vector fields
Current License: CC BY-SA 3.0
6 events
| when toggle format | what | by | license | comment | |
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| Jun 25, 2013 at 3:02 | review | Late answers | |||
| Jun 25, 2013 at 4:50 | |||||
| Dec 1, 2011 at 16:34 | history | edited | gggg gggg | CC BY-SA 3.0 |
added 358 characters in body
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| Dec 1, 2011 at 16:32 | comment | added | gggg gggg | Yes, sorry, you are absolutely right, Ben, I was a bit confused and, apparently, I have messed the terms group and algebra. I will edit the answer to avoid misunderstandings. Thanks for the comment! | |
| Nov 28, 2011 at 23:49 | comment | added | MTS | @Ben: Sorry to nitpick, but I think you mean $SL(2,\mathbb{R})$ rather than $SL(2,\mathbb{C})$. $SL(2,\mathbb{C})$ is simply connected and hence is its own universal cover. | |
| Nov 28, 2011 at 19:21 | comment | added | Ben McKay | Not quite. The universal covering group of $SL(2,\mathbb{C})$ is not a subgroup of any $GL(n)$. However, it is true that every Lie algebra has a faithful representation (Ado's theorem), and that every Lie group has a representation with discrete kernel, so that suffices to prove the result. However, much more elementary proofs suffice. | |
| Nov 28, 2011 at 18:00 | history | answered | gggg gggg | CC BY-SA 3.0 |