Timeline for What is π_1(BG) for an arbitrary topological group $G$?
Current License: CC BY-SA 3.0
3 events
| when toggle format | what | by | license | comment | |
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| Nov 25, 2011 at 19:07 | comment | added | Ronnie Brown | Misprint: $\tilede{ G}$ should be $\tilde{G}$. | |
| Nov 25, 2011 at 19:06 | comment | added | Ronnie Brown | I should have added that the $k$-invariant referred to is exactly the obstruction to there being a `universal covering' topological group $\tilede G$ of $G$ (in the sense that there is a morphism $p: \tilde{ G} \to G$ of topological groups which on each component is a universal cover of spaces). | |
| Nov 25, 2011 at 17:28 | history | answered | Ronnie Brown | CC BY-SA 3.0 |