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Dec 14, 2011 at 7:10 comment added Matthias Künzer On the other hand, for which categories I is Top^I -> Ho(Top)^I dense? I.e. what is the condition on I that ensures that there is never an obstruction against rectifying a diagram of shape I? Cf. also mathoverflow.net/questions/39431/… .
Dec 8, 2011 at 11:49 answer added Jesper Grodal timeline score: 14
Dec 3, 2011 at 4:17 vote accept Akhil Mathew
Dec 2, 2011 at 22:43 answer added Jeff Smith timeline score: 19
Nov 26, 2011 at 20:05 answer added Tom Goodwillie timeline score: 18
Nov 26, 2011 at 16:14 history edited Akhil Mathew CC BY-SA 3.0
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Nov 24, 2011 at 1:01 answer added Dylan Wilson timeline score: 10
Nov 23, 2011 at 22:14 comment added Tom Goodwillie A naturally occurring example of a functor $\mathcal I\to Ho(Top)$ is the one where $\mathcal I$ is the category of abelian groups and the functor takes $G$ to a Moore space: a simply connected space whose only nontrivial homology group is $H_n\cong G$ for some fixed $n\ge 2$. People have studied the obstructions to strictifying this. There are probably pretty small diagrams of abelian groups for which it can't be done. Google "equivariant Moore space".
Nov 23, 2011 at 20:02 answer added Tyler Lawson timeline score: 12
Nov 23, 2011 at 19:28 comment added Clark Barwick The obstructions to which you allude in your first paragraph are introduced in Dwyer-Kan, "Realizing diagrams in the homotopy category by means of diagrams of simplicial sets," MR0744648, and "An obstruction theory for diagrams of simplicial sets," MR0749527. Your example can be adapted in the following way: any H-space that is not an A_n-space defines a functor $\Delta_{\leq n}\to\mathrm{Ho}\mathcal{S}$ that cannot be rectified.
Nov 23, 2011 at 17:30 comment added Oscar Randal-Williams See the discussion starting on p.401 of: Cooke, George Replacing homotopy actions by topological actions. Trans. Amer. Math. Soc. 237 (1978), 391–406.
Nov 23, 2011 at 17:16 history asked Akhil Mathew CC BY-SA 3.0