Timeline for functional iteration
Current License: CC BY-SA 3.0
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Nov 22, 2011 at 11:15 | comment | added | Pietro Majer | btw, this question seems more suitable for math.stackexchange.com | |
Nov 22, 2011 at 11:04 | comment | added | Pietro Majer | Note that $F(x) < x $ on $I:=(-1/q,0)$ so starting from $x \in I$ the iteration $x_n$ converges just because it is decreasing and bounded below. The limit is $-1/q$ as it is the unique negative fixed point. Since $F'(-1/q)=0$ there is quadratic convergence. Also note that all the $F_q$ are conjugated, so it suffices to consider $q=1$. | |
Nov 22, 2011 at 4:29 | history | asked | gazerik | CC BY-SA 3.0 |