Timeline for Jordan form of compact operator [closed]
Current License: CC BY-SA 3.0
12 events
when toggle format | what | by | license | comment | |
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Nov 24, 2011 at 20:26 | vote | accept | Alexander | ||
Nov 22, 2011 at 18:46 | history | closed |
Bill Johnson Yemon Choi Andrés E. Caicedo user6976 Ryan Budney |
too localized | |
Nov 21, 2011 at 21:01 | vote | accept | Alexander | ||
Nov 24, 2011 at 20:26 | |||||
S Nov 21, 2011 at 21:00 | vote | accept | Alexander | ||
Nov 21, 2011 at 21:01 | |||||
Nov 21, 2011 at 21:00 | vote | accept | Alexander | ||
S Nov 21, 2011 at 21:00 | |||||
Nov 21, 2011 at 10:45 | comment | added | Christopher A. Wong | What do you mean by canonical basis? There is certainly more than one choice of eigenbasis if you just have a two-dimensional eigenspace, for example. | |
Nov 21, 2011 at 10:04 | history | edited | Alexander | CC BY-SA 3.0 |
added 80 characters in body
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Nov 20, 2011 at 23:36 | comment | added | Yemon Choi | I'm also not quite sure what you're looking for with your questions; perhaps I have misunderstood something. We know that for the non-zero eigenvalues, the eigenspaces are finite-dimensional; so all the theory for the finite-dimensional case applies on each such eigenspace. On the other hand, one can have quasinilpotent compact operators on Banach spaces and there all bets are off unless one knows more about the invariant subspaces of the operator (like the Volterra case mentioned in on eof the answers) | |
Nov 20, 2011 at 23:32 | comment | added | Yemon Choi | Ringrose's little book "Compact non-self-adjoint operators" has a good exposition of how things work in the Hilbert space case. The basics of the theory for compact operators on general Banach spaces is in Rudin's Functional Analysis, if I recall correctly. | |
Nov 20, 2011 at 20:53 | answer | added | Anatoly Kochubei | timeline score: 0 | |
Nov 20, 2011 at 20:00 | answer | added | Florian | timeline score: 2 | |
Nov 20, 2011 at 16:17 | history | asked | Alexander | CC BY-SA 3.0 |