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Jun 6, 2021 at 10:43 comment added Sasha @DavidWhite with some delay, I showed up to accept it :)
Jun 6, 2021 at 10:42 vote accept Sasha
Apr 13, 2017 at 12:19 history edited CommunityBot
replaced http://math.stackexchange.com/ with https://math.stackexchange.com/
Nov 29, 2011 at 10:08 history edited Pierre-Yves Gaillard CC BY-SA 3.0
typo
Nov 26, 2011 at 6:51 history edited Pierre-Yves Gaillard CC BY-SA 3.0
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Nov 25, 2011 at 12:42 history edited Pierre-Yves Gaillard CC BY-SA 3.0
typo
Nov 24, 2011 at 11:37 history edited Pierre-Yves Gaillard CC BY-SA 3.0
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Nov 23, 2011 at 6:04 comment added Pierre-Yves Gaillard Dear @Todd: I agree with you, especially with the "including proofs". I hope you will write something up for the nLab. If you do, thank you in advance for letting us know.
Nov 22, 2011 at 21:23 comment added Todd Trimble Yes, please do share your thoughts, David. I'm following this discussion and would be very interested in collecting information (including proofs), so that I can write something up for the nLab. (Of course, anyone can get involved with the nLab.)
Nov 22, 2011 at 14:37 comment added Pierre-Yves Gaillard Dear @David: Thank you very much for your kind comments! You seem to have a lot to say about this. I hope you'll post an answer of your own in a not too distant future. I appreciate all the comments you've made so far in this thread.
Nov 22, 2011 at 14:22 comment added David White An example for (c) is in the linked paper: Lemma 1.2 and the remark afterwards that one of the inclusions is strict. The key observation seems to be that if you take the union of a strictly increasing $\kappa$-chain of sumpact modules (a.k.a. dually slender), then this is also sumpact. An example is the union of $\kappa$ many cyclic submodules. If $\kappa$ is uncountable then this module clearly is not finitely generated. I looked in T.Y.Lam's Lectures on Modules and Rings for a simpler example, but it's not there. Still, the example above is not so bad, & any example will need set theory
Nov 22, 2011 at 14:04 comment added David White +1: This is a great answer. I've been wondering about this sumpact problem for a while, and I'm glad to see it settled. I hope Sasha shows up to accept this; it completely answers what he wanted. I'll see if I can figure out an example to answer (c). I suppose it's worth noting (from the OP's original question) that (a) and (b) are equivalent if $R$ is perfect, which is pretty cool
Nov 22, 2011 at 6:43 history edited Pierre-Yves Gaillard CC BY-SA 3.0
edit clearly indicated
Nov 20, 2011 at 11:24 history edited Pierre-Yves Gaillard CC BY-SA 3.0
edit clearly indicated
Nov 19, 2011 at 11:32 history answered Pierre-Yves Gaillard CC BY-SA 3.0