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Nov 17, 2011 at 14:32 comment added Charles Nevermind, I see the advantage -- Theorem 1.2 is slightly faster though works under more restrictive conditions. The formula I meant was $\pi(x)\equiv \sum_{m\le\sqrt x}\mu(m)\sum_{n\le\sqrt{x/m^2}} \left\lfloor\frac{x}{nm^2}\right\rfloor\pmod2.$
Nov 16, 2011 at 21:55 comment added user9072 @Charles: You are welcome. I am sorry I cannot answer the follow-up; what formula do you mean? (I tried to search but first all I found was physics-things, then also prime things but not really sure what is meant.)
Nov 16, 2011 at 19:37 comment added Charles So basically Theorem 1.2 has no advantage over using Lifchitz's formula twice?
Nov 16, 2011 at 18:10 vote accept Charles
Nov 16, 2011 at 18:10 comment added Charles That's the condition I missed. Thanks!
Nov 16, 2011 at 17:49 history answered user9072 CC BY-SA 3.0