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May 31, 2023 at 22:20 comment added cody and $\mathrm{PA}$ does not prove that induction up to $\epsilon_0$ is well-founded for any "reasonable" notation system for it, though it can express that statement.
May 31, 2023 at 22:18 comment added cody $\epsilon_0$ does have a finitary representation of a similar sort! It is a computable ordinal and quite low on the Veblen hierarchy (see e.g. this). However it does not have a Cantor normal form (and is the first such ordinal), so the notation needs to be different from that one.
Jul 24, 2019 at 20:55 comment added Thomas Benjamin @DavidE.Speyer: Since on your blog post, $\omega^{\omega}$ is represented by the list (((()))), is there some reason why $\epsilon_0$ cannot have a 'finitary' representation of a similar sort?
Dec 7, 2009 at 16:25 history answered David E Speyer CC BY-SA 2.5