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Nov 25, 2011 at 16:04 comment added David Carchedi @Vitali: This question is a bit vague on purpose. Essentially, if there happens to be a way to compute the cohomology of the interior of the zero set of each smooth function on R^n, then this would give a way of computing the cohomology of $B\Gamma^n$.
Nov 24, 2011 at 21:26 comment added Vitali Kapovitch the question is a bit too vague. of course a strong condition on f will say something about level and sublevel sets. e.g. if f is convex then the sublevel sets are convex and hence contractible. what do you really know about f in your situation? personally, I have used a variation of the above when f is partially k-convex which implied that sublevel sets have homotopy types of k-dimensional CW-complexes.
Nov 17, 2011 at 20:07 answer added Tara Holm timeline score: 3
Nov 16, 2011 at 22:15 comment added David Carchedi Thanks Otis, but in fact I'm aware of this. See my comment to the answer of algori.
Nov 16, 2011 at 18:58 answer added algori timeline score: 1
Nov 16, 2011 at 18:57 comment added Otis Chodosh Keep in mind that all closed sets are the zero set of a smooth function.
Nov 16, 2011 at 17:03 history asked David Carchedi CC BY-SA 3.0