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Apr 22, 2021 at 9:37 comment added Pietro Majer Actually no comment
Apr 7, 2021 at 23:11 comment added Yemon Choi Apologies for coming back to very old material, but do you have any comment on the the answers below which claim that there is something amiss in your answer?
Nov 4, 2015 at 14:53 comment added tomglabst You can find this in Adams, Sobolev Spaces.
Jan 7, 2015 at 15:32 comment added Pietro Majer @QA Ngô In fact, $u_\epsilon\to0$ a.e., in $L^{p^*}$, and in $W^{1,p}$, as $\epsilon\to0$. The claim is on the normalized family: check the last lines.
Jan 7, 2015 at 12:56 comment added QA Ngô In this answer, it is not clear to see why the sequence $\{u_\varepsilon\}_\varepsilon$ has no convergent subsequence in $L^{p^\star}$. Basically, there are two types of lacking the compactness property: Unbounded domains and critical exponents. In both cases, it is more convenient to dilate a "good" function plus a scaling of this function if working in bounded domains.
Sep 5, 2013 at 17:16 history edited Pietro Majer CC BY-SA 3.0
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Nov 16, 2011 at 16:16 history edited Pietro Majer CC BY-SA 3.0
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Nov 16, 2011 at 10:15 history edited Pietro Majer CC BY-SA 3.0
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Nov 16, 2011 at 7:24 history answered Pietro Majer CC BY-SA 3.0