Timeline for morphism from a compact group to Z ?
Current License: CC BY-SA 3.0
9 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jan 22, 2015 at 22:20 | answer | added | Sean Eberhard | timeline score: 23 | |
| Nov 17, 2011 at 7:49 | vote | accept | Florent MARTIN | ||
| Nov 17, 2011 at 7:49 | vote | accept | Florent MARTIN | ||
| Nov 17, 2011 at 7:49 | |||||
| Nov 15, 2011 at 12:33 | answer | added | Alain Valette | timeline score: 42 | |
| Nov 15, 2011 at 9:54 | vote | accept | Florent MARTIN | ||
| Nov 17, 2011 at 7:49 | |||||
| Nov 15, 2011 at 9:53 | comment | added | Florent MARTIN | Thanks. However, if I got it well I can use Dudley's theorem has, if G is metric and complete, a morphism from G to Z is continuous? For Dudley's theorem I found this math.univ-lyon1.fr/~melleray/rapport-LeMaitre.pdf , part 3. Otherwise, there is the following (part 3 too), but I didn't understand the proof : math.univ-lyon1.fr/~melleray/Rosendal.pdf | |
| Nov 15, 2011 at 9:39 | answer | added | Andreas Thom | timeline score: 52 | |
| Nov 15, 2011 at 9:11 | comment | added | Julien Melleray | If G is metrizable then the answer is no - by Dudley's theorem, $\phi$ must be continuous hence is zero everywhere. I don't know what happens in general. | |
| Nov 15, 2011 at 9:01 | history | asked | Florent MARTIN | CC BY-SA 3.0 |