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Apr 23, 2012 at 13:57 history edited paul garrett CC BY-SA 3.0
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Apr 22, 2012 at 20:34 history edited paul garrett CC BY-SA 3.0
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Apr 22, 2012 at 14:00 comment added Bazin I disagree with Paul Garrett answer: the Fourier transform of $\vert x\vert^s$ on $\mathbb R^n$ is a constant multiple of $$ \vert x\vert^{-s-n}, $$ not $\vert x\vert^{s-n}$ as written in his answer. To have both sides locally integrable, we need $$ -n<\Re s<0. $$ Bazin.
Nov 14, 2011 at 16:44 vote accept Igor Rivin
Nov 14, 2011 at 16:44 comment added Igor Rivin Ah, the edit is very illuminating!
Nov 14, 2011 at 15:42 history edited paul garrett CC BY-SA 3.0
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Nov 14, 2011 at 15:23 comment added Igor Rivin Yes, I am aware of why this is defined, what I wonder about is how does one actually go about computing these things.
Nov 14, 2011 at 14:37 history answered paul garrett CC BY-SA 3.0