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Nov 10, 2011 at 22:10 comment added Mike Crumley I think there is a great deal of confusion concerning notation (which is my fault, I apologize). I will try to reformulate the question in terms of comodules over the representing Hopf algebras of the groups.
Nov 10, 2011 at 18:07 comment added Chuck Hague I agree, I don't think it's true even in the case that the $G \times H$-representation is indecomposable. My guess is that the following statement is true: Any representation of $G \times H$ has a filtration with subquotients isomorphic to modules of the form $V \otimes W$.
Nov 10, 2011 at 17:39 comment added David Jordan Perhaps the OP meant to consider only irreducible representations of $G\times H$? With the appropriate assumptions, every irreducible representation of $G\times H$ is obtained as an external product of irreducibles of $G$ and $H$. However, I think it's not true in general, even if you restrict to indecomposables of $G\times H$.
Nov 10, 2011 at 17:29 history answered Chuck Hague CC BY-SA 3.0