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Nov 9, 2011 at 21:48 comment added Vít Tuček Yes, you are right. I've corrected the formula. I do not claim that this formula gives you what you want. It just popped up in my head when I read your question and I thought it might help you in your case. Anyway - from the decomposition of $A$ it is clear that what you really care about is how the projection $P$ of your measurable set $S$ changes its volume.
Nov 9, 2011 at 21:42 history edited Vít Tuček CC BY-SA 3.0
wrong dimensions in the last sentence
Nov 9, 2011 at 21:33 comment added Grigory Yaroslavtsev Thank you, but I am not sure I understand how can this be used to compute the $\mathcal{L}^m(f(S))$, which I am interested in. Also, shouldn't the formula have $\mathcal{H}^{n - m}$, rather than $\mathcal{H}^{m - n}$ on the left-hand side?
Nov 9, 2011 at 20:06 history edited Vít Tuček CC BY-SA 3.0
added 581 characters in body
Nov 9, 2011 at 19:54 history edited Vít Tuček CC BY-SA 3.0
deleted 23 characters in body
Nov 9, 2011 at 19:44 history answered Vít Tuček CC BY-SA 3.0