Timeline for Continuation of a smooth function
Current License: CC BY-SA 4.0
14 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| S Mar 13 at 13:27 | history | suggested | The Amplitwist | CC BY-SA 4.0 |
fixed broken link to Wikipedia
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| Mar 13 at 11:10 | review | Suggested edits | |||
| S Mar 13 at 13:27 | |||||
| Feb 29, 2012 at 3:53 | vote | accept | Kirill Shmakov | ||
| Nov 13, 2011 at 21:02 | vote | accept | Kirill Shmakov | ||
| Feb 29, 2012 at 3:53 | |||||
| Nov 13, 2011 at 21:00 | vote | accept | Kirill Shmakov | ||
| Nov 13, 2011 at 21:02 | |||||
| Nov 13, 2011 at 0:59 | vote | accept | Kirill Shmakov | ||
| Nov 13, 2011 at 21:00 | |||||
| Nov 10, 2011 at 17:54 | history | edited | Kirill Shmakov | CC BY-SA 3.0 |
Update
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| Nov 9, 2011 at 18:30 | answer | added | Igor Khavkine | timeline score: 1 | |
| Nov 8, 2011 at 20:52 | answer | added | Christopher A. Wong | timeline score: 1 | |
| Nov 8, 2011 at 18:10 | comment | added | Deane Yang | If you know more about the domains (like explicit formulas or global co-ordinates), you don't need to use a partition of unity. You can probably do what Stein does locally but do it globally. | |
| Nov 8, 2011 at 17:52 | comment | added | Kirill Shmakov | @Dean Yang Thanks, the parity of unity answers the question of existence. Although from computational point of view it doesn't look very helpful . | |
| Nov 8, 2011 at 17:20 | comment | added | Denis Serre | For finite order smoothness, the Babitch extension does the job. It is used to extend Sobolev functions $u\in H^s(\Omega)$ to $H^s({\mathbb R}^n)$. | |
| Nov 8, 2011 at 17:14 | comment | added | Deane Yang | Look in Stein, "Singular integrals and differentiability properties of functions" | |
| Nov 8, 2011 at 17:07 | history | asked | Kirill Shmakov | CC BY-SA 3.0 |