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Todd Trimble
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Let $W$ be a Coxeter group attached to a Coxeter matrix with entries $m_{ij}$ . The presentation of $W$ is given by $$W= < T_1, \dots, T_n | T_i^2=1, (T_iT_j)^{m_{ij}}=1, i \neq j>$$$$W= < T_1, \dots, T_n | T_i^2=1, T_iT_jT_i \ldots = T_jT_iT_j \ldots, i \neq j>$$ where each side of the second equation has $m_{ij}$ terms.

Suppose $B_{W}$ is the corresponding braid group  (or calledaka Artin group) obtained by removing the relations $T_i^2=1$, that is, $$B_{W}=< T_1, \dots, T_n | T_iT_jT_i \cdots = T_jT_iT_j \cdots>,$$: where each sides have $m_{ij}$ terms.$$B_{W}=< T_1, \dots, T_n | T_iT_jT_i \cdots = T_jT_iT_j \cdots>.$$

Then there is a canonical surjective homomorphism $B_{W} \to W$, the kernel of this homomorphism is called pure Artin group.

Does anyone know the presentation of the pure Artin group?

Thank you!

Let $W$ be a Coxeter group attached to a Coxeter matrix with entries $m_{ij}$ . The presentation of $W$ is given by $$W= < T_1, \dots, T_n | T_i^2=1, (T_iT_j)^{m_{ij}}=1, i \neq j>$$

Suppose $B_{W}$ is the corresponding braid group(or called Artin group) obtained by removing the relations $T_i^2=1$, that is, $$B_{W}=< T_1, \dots, T_n | T_iT_jT_i \cdots = T_jT_iT_j \cdots>,$$ where each sides have $m_{ij}$ terms.

Then there is a canonical surjective homomorphism $B_{W} \to W$, the kernel of this homomorphism is called pure Artin group.

Does anyone know the presentation of the pure Artin group?

Thank you!

Let $W$ be a Coxeter group attached to a Coxeter matrix with entries $m_{ij}$ . The presentation of $W$ is given by $$W= < T_1, \dots, T_n | T_i^2=1, T_iT_jT_i \ldots = T_jT_iT_j \ldots, i \neq j>$$ where each side of the second equation has $m_{ij}$ terms.

Suppose $B_{W}$ is the corresponding braid group  (aka Artin group) obtained by removing the relations $T_i^2=1$: $$B_{W}=< T_1, \dots, T_n | T_iT_jT_i \cdots = T_jT_iT_j \cdots>.$$

Then there is a canonical surjective homomorphism $B_{W} \to W$, the kernel of this homomorphism is called pure Artin group.

Does anyone know the presentation of the pure Artin group?

Thank you!

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Let $W$ be a Coxeter group attached to a Coxeter matrix with entries $m_{ij}$ . The presentation of $W$ is given by $$W= < T_1, \dots, T_n | T_i^2=1, (T_iT_j)^{m_{ij}}=1, i \neq j>$$

Suppose $B_{W}$ is the corresponding braid group(or called Artin group) obtained by removing the relations $T_i^2=1$, that is, $$B_{W}=< T_1, \dots, T_n | (T_iT_j)^{m_{ij}}=1, i \neq j>$$$$B_{W}=< T_1, \dots, T_n | T_iT_jT_i \cdots = T_jT_iT_j \cdots>,$$ where each sides have $m_{ij}$ terms.

Then there is a canonical surjective homomorphism $B_{W} \to W$, the kernel of this homomorphism is called pure Artin group.

Does anyone know the presentation of the pure Artin group?

Thank you!

Let $W$ be a Coxeter group attached to a Coxeter matrix with entries $m_{ij}$ . The presentation of $W$ is given by $$W= < T_1, \dots, T_n | T_i^2=1, (T_iT_j)^{m_{ij}}=1, i \neq j>$$

Suppose $B_{W}$ is the corresponding braid group(or called Artin group) obtained by removing the relations $T_i^2=1$, that is, $$B_{W}=< T_1, \dots, T_n | (T_iT_j)^{m_{ij}}=1, i \neq j>$$

Then there is a canonical surjective homomorphism $B_{W} \to W$, the kernel of this homomorphism is called pure Artin group.

Does anyone know the presentation of the pure Artin group?

Thank you!

Let $W$ be a Coxeter group attached to a Coxeter matrix with entries $m_{ij}$ . The presentation of $W$ is given by $$W= < T_1, \dots, T_n | T_i^2=1, (T_iT_j)^{m_{ij}}=1, i \neq j>$$

Suppose $B_{W}$ is the corresponding braid group(or called Artin group) obtained by removing the relations $T_i^2=1$, that is, $$B_{W}=< T_1, \dots, T_n | T_iT_jT_i \cdots = T_jT_iT_j \cdots>,$$ where each sides have $m_{ij}$ terms.

Then there is a canonical surjective homomorphism $B_{W} \to W$, the kernel of this homomorphism is called pure Artin group.

Does anyone know the presentation of the pure Artin group?

Thank you!

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Let $W$ be a Coxeter group attached to a Coxeter matrix with entries $m_{ij}$ . The presentation of an Artin group $W$ is given by $$W= < T_1, \dots, T_n | T_i^2=1, (T_iT_j)^{m_{ij}}=1, i \neq j>$$

Suppose $B_{W}$ is the corresponding braid group(or generalized braidcalled Artin group) obtained by removing the relations $T_i^2=1$, that is well known:, $$B_{W}=< T_1, \dots, T_n | T_iT_jT_i\cdots = T_jT_iT_j \cdots >$$ where each sides have$$B_{W}=< T_1, \dots, T_n | (T_iT_j)^{m_{ij}}=1, i \neq j>$$

Then there is a canonical surjective homomorphism $m_{ij}$terms$B_{W} \to W$, $m_{ij}= 2, 3, 4, 6 .$ and $W$ is the Weylkernel of this homomorphism is called pure Artin group.

Does anyone know the presentation of the pure Artin group, that is, the fundamental group of $\mathbb{C}^n$ removing the walls of the Weyl chambers?

Thank you!

The presentation of an Artin group (or generalized braid group) is well known: $$B_{W}=< T_1, \dots, T_n | T_iT_jT_i\cdots = T_jT_iT_j \cdots >$$ where each sides have $m_{ij}$terms, $m_{ij}= 2, 3, 4, 6 .$ and $W$ is the Weyl group.

Does anyone know the presentation of the pure Artin group, that is, the fundamental group of $\mathbb{C}^n$ removing the walls of the Weyl chambers?

Thank you!

Let $W$ be a Coxeter group attached to a Coxeter matrix with entries $m_{ij}$ . The presentation of $W$ is given by $$W= < T_1, \dots, T_n | T_i^2=1, (T_iT_j)^{m_{ij}}=1, i \neq j>$$

Suppose $B_{W}$ is the corresponding braid group(or called Artin group) obtained by removing the relations $T_i^2=1$, that is, $$B_{W}=< T_1, \dots, T_n | (T_iT_j)^{m_{ij}}=1, i \neq j>$$

Then there is a canonical surjective homomorphism $B_{W} \to W$, the kernel of this homomorphism is called pure Artin group.

Does anyone know the presentation of the pure Artin group?

Thank you!

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