Timeline for convexity of images of space-filling curves
Current License: CC BY-SA 3.0
12 events
| when toggle format | what | by | license | comment | |
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| Jun 15, 2020 at 7:27 | history | edited | CommunityBot |
Commonmark migration
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| S Jan 15, 2018 at 18:06 | history | suggested | jeq | CC BY-SA 3.0 |
Copied image to imgur.com, as it was not being displayed because of the new https rule.
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| Jan 15, 2018 at 17:08 | review | Suggested edits | |||
| S Jan 15, 2018 at 18:06 | |||||
| Sep 5, 2013 at 17:22 | history | edited | Pietro Majer | CC BY-SA 3.0 |
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| Nov 23, 2011 at 7:39 | comment | added | Pietro Majer | Thank you. It remains a problem: conversely, is the set $C$ nowhere dense? We may also state the problem in a slightly general form: suppose $A(t)$, for $0\le t \le 1$, is a family of convex sets, with $A(t)\subset A(s)$ for $t\le s$, and $A(0)$={0} and $A(1)$= the unit ball. Suppose $f$ is a selection curve of $\partial A$: for all $t$, $f(t)\in\partial A(t)$. Can one have $f([0,1])=A(1)$ ? | |
| Nov 23, 2011 at 1:45 | vote | accept | Michael Hardy | ||
| Nov 4, 2011 at 11:22 | history | edited | Pietro Majer | CC BY-SA 3.0 |
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| Nov 4, 2011 at 2:43 | comment | added | Michael Hardy | Tonight I'm nowhere near a printer. I'll print this tomorrow so I can look it over while making marginal notes as that becomes convenient and then see if I have any comments or questions. Maybe the hard part is proving that the set in question is always nowhere dense. | |
| Nov 3, 2011 at 21:12 | history | edited | Pietro Majer | CC BY-SA 3.0 |
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| Nov 3, 2011 at 19:39 | history | edited | Pietro Majer | CC BY-SA 3.0 |
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| Nov 3, 2011 at 19:11 | history | edited | Pietro Majer | CC BY-SA 3.0 |
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| Nov 3, 2011 at 19:06 | history | answered | Pietro Majer | CC BY-SA 3.0 |