Timeline for Analytic continuation of ordinary Dirichlet series
Current License: CC BY-SA 3.0
8 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Nov 4, 2011 at 2:14 | comment | added | Y. Zhao | @Johan Andersson:Thank you so much!It is a clear and useful counterexample. | |
| Nov 4, 2011 at 2:09 | vote | accept | Y. Zhao | ||
| Nov 3, 2011 at 20:06 | history | edited | Johan Andersson | CC BY-SA 3.0 |
added 792 characters in body; edited body
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| Nov 3, 2011 at 19:42 | comment | added | GH from MO | @Paul: I had a similar comment that I deleted! | |
| Nov 3, 2011 at 18:46 | comment | added | paul garrett | @GH Thanks for helping me out! Sorry for the inattention... :) I removed my silly question-comment. | |
| Nov 3, 2011 at 18:42 | comment | added | GH from MO | @Paul: He considers $\exp(\eta(s))$, not $\eta(s)$. | |
| Nov 3, 2011 at 18:41 | comment | added | Johan Andersson | well an entire function is of finite order if $f(s) \ll e^{|s|^c}$ for some $c>0$. I am not quite sure about the meromorphic analogue, but in case the meromorphic function is entire they should surely coincide. Of course even if $f(s) \ll e^{|s|^c}$ is of finite order the exponential $e^{f(s)}$ of this function should not in general be of finite order (unless $f(s)$ is a polynomial). | |
| Nov 3, 2011 at 18:11 | history | answered | Johan Andersson | CC BY-SA 3.0 |