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Nov 3, 2011 at 18:00 comment added Bill Johnson That's right, Jason.
Nov 3, 2011 at 14:30 comment added Jason Rute Thanks! I assume $B\sim C$ is set subtraction. I feel a bit silly for not noticing this construction. Also, by my comment to Nate above, the space has size continuum, so the density character is exactly the continuum.
Nov 3, 2011 at 13:51 vote accept Jason Rute
Nov 3, 2011 at 13:33 history answered Bill Johnson CC BY-SA 3.0