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Nov 4, 2011 at 13:29 comment added Robert Israel Using Maple, I looked for $v_4 = (a,b,0)^T$, $v_5 = (c,d,e)^T$ for which the determinant of a symmetric solution $G$ is identically 0.
Nov 3, 2011 at 1:36 vote accept Kap
Nov 2, 2011 at 23:37 comment added Jacques Carette How did you arrive at this solution? I guess I really mean: where did v4 and v5 come from?
Nov 2, 2011 at 23:32 history answered Robert Israel CC BY-SA 3.0