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Nov 1, 2011 at 11:15 history edited Steven Landsburg CC BY-SA 3.0
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Nov 1, 2011 at 6:13 comment added Adam Hughes Alex: yes, sorry, I messed up my notation, I meant the field extension without the "Gal" bit at the beginning.
Nov 1, 2011 at 3:59 comment added Harry Altman Surely we need that k has no nontrivial nilpotents?
Nov 1, 2011 at 2:31 comment added Alex If S is required to be a subfield, then of course you get uniqueness, but I still don't see a natural condition that would guarantee existence. Besides, you wrote that your motivating example if the absolute Galois group of $\mathbb{Q}$, but you would need your subgroup to be commutative if it has to be the group of units in a field. Maybe I totally misunderstood, but I don't really see what you're trying to do.
Nov 1, 2011 at 2:07 comment added Adam Hughes (and of course S should be required to be a subfield)
Nov 1, 2011 at 1:45 comment added Adam Hughes M Turgeon: if R is required to be a field that circumvents the problem with $k[x]$, so there is hope in that direction.
Nov 1, 2011 at 1:38 comment added M Turgeon @Adam: This is just my gut feeling, but I don't think many interesting hypotheses on your ring could circumvent Steven's counterexample to Uniqueness...
Nov 1, 2011 at 0:34 comment added Adam Hughes That's great for general rings, and I thought I said this, but I apparently did not: can I include assumptions on $R$ which will make it hold true. I'll edit the original question. Thanks!
Nov 1, 2011 at 0:26 history answered Steven Landsburg CC BY-SA 3.0