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Nov 1, 2011 at 4:07 comment added Mike Shulman Qfwfq: Yes, it is. In fact, for any geometric morphism $f:X\to Y$, we can pick any site $S_Y$ generating $Y$, and then there exists a site $S_X$ generating $X$ for which $f$ is induced by a map of sites $S_Y\to S_X$.
Oct 31, 2011 at 21:30 history edited JBorger CC BY-SA 3.0
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Oct 31, 2011 at 18:16 comment added Qfwfq If the above is true, it reminds me of the fact that you can present (nice) topological spaces $X,Y$ as simplicial complexes $S_X,S_Y$ but if the latter are too "coarse" there may be maps $f:X\to Y$ that are not realized (up to homotopy) by simplicial maps $S_X\to S_Y$; nevertheless you can always present $X$ and $Y$ by "finer" simplicial complexes such that a simplicial approximation to $f$ does exist.
Oct 31, 2011 at 18:11 comment added Qfwfq Is it true that for every (Grothendieck) topos morphism $f:X\to Y$ you can choose sites $S_X$ and $S_Y$, with $X=Sh(S_X)$ and $Y=Sh(S_Y)$, such that $f$ comes from a morphism of sites $\varphi: S_X\to S_Y$ ?
Oct 31, 2011 at 11:48 comment added Yosemite Sam +1 - I guess one could also take $\mathbb{R}^n$ and the sites of open subsets and open balls.
Oct 31, 2011 at 8:01 history answered JBorger CC BY-SA 3.0