Timeline for positive hermitian elements in $M_n(\mathbb{C})$
Current License: CC BY-SA 3.0
6 events
when toggle format | what | by | license | comment | |
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Oct 30, 2011 at 8:26 | answer | added | Zack Wolske | timeline score: 1 | |
Oct 29, 2011 at 19:48 | comment | added | Jack Poulson | The set of upper (lower) triangular matrices with non-negative diagonals satisfies (i), (ii), and (iii) trivially since the eigenvalues lie on the diagonal. If we call the set of such upper triangular matrices $\mathcal U$, and the set of such lower triangular matrices $\mathcal L$, then we have a variant of (iv) which is $\mathcal U + -\mathcal U + i \mathcal U + -i \mathcal U + \mathcal L + -\mathcal L + i \mathcal L + -i \mathcal L = M_n(\mathbb C)$. | |
Oct 29, 2011 at 14:21 | comment | added | Suvrit | ah, ok. i did not read (iv) at all :-) | |
Oct 29, 2011 at 13:54 | comment | added | spelas | But $x^∗ax$ is also hermitian matrix if $a$ is. So $x^∗Px⊂P$, and $x^∗M_n(\mathbb{C})x=M_n(\mathbb{C})$ iff $x$ is invertible. So $x^∗Px$ either does not satisfy (iv) or equals $P$. | |
Oct 29, 2011 at 13:07 | comment | added | Suvrit | $X^*AX \ge 0$ for all $X$ if $A \ge 0$. | |
Oct 29, 2011 at 12:01 | history | asked | spelas | CC BY-SA 3.0 |