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Nov 23, 2011 at 16:47 vote accept Thomas Kahle
Oct 29, 2011 at 18:11 answer added Gjergji Zaimi timeline score: 2
Oct 29, 2011 at 13:42 history edited Thomas Kahle CC BY-SA 3.0
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Oct 29, 2011 at 13:40 comment added Graham Leuschke I guess my previous comment only applies if $S$ is a finitely generated $A$-module, that is, some power of each $x_j$ is in $A$.
Oct 29, 2011 at 10:50 comment added Graham Leuschke In characteristic zero, normality is also enough. The norm map on quotient fields restricts to a splitting of rings. Of course this has nothing to do with the special form of $A$.
Oct 29, 2011 at 8:46 history asked Thomas Kahle CC BY-SA 3.0