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Oct 20, 2012 at 11:01 comment added Timothy Foo Thanks so much for your comment. I actually saw your question but couldn't say anything noteworthy about it off the top of my head. What wonderful implications what you wrote has. I hope that there will be more interesting facts that will emerge, whether on MO or not, in regards to this topic. Thanks again.
Oct 14, 2012 at 20:25 comment added js21 A bit late, but I asked recently mathoverflow.net/questions/106359/… for an evaluation of the sum of $\left( \frac{.}{p} \right)$ over intervals $aq <n <bq$. What I wrote in my question implies that the answer to your question for $\beta= \frac{1}{6}$ depends only on $p \mod 24$.
Oct 28, 2011 at 7:46 comment added Yemon Choi Fixed your LaTeX - the trick is to put backtick marks around your displayed maths
Oct 28, 2011 at 7:45 history edited Yemon Choi CC BY-SA 3.0
fixed the LaTeX and tweaked teh link
Oct 28, 2011 at 6:53 comment added Timothy Foo The second one: $$L\left(\left(\frac{\cdot}{q}\right),1\right) = \frac{\pi}{q^{1/2}\left(r-\left(\frac{r}{q}\right)\right)}\sum_{0<m<q/2}\left(\frac{m}{q}\right)\left(r-1-2\left\lfloor\frac{mr}{q}\right\rfloor\right)$$ and the third one: $$ L\left(\left(\frac{\cdot}{q}\right),1\right) = \frac{2\pi}{q^{1/2}\left(3-\left(\frac{3}{q}\right)\right)}\sum_{0<m<q/3}\left(\frac{m}{q}\right)$$
Oct 28, 2011 at 6:52 comment added Timothy Foo I can't seem to make the first three equations display properly. Here is the first one: $$L\left(\left(\frac{\cdot}{q}\right),1\right) = \frac{\pi}{q^{1/2}\left(2-\left(\frac{2}{q}\right)\right)}\sum_{0<m<q/2}\left(\frac{m}{q}\right)$$
Oct 28, 2011 at 6:45 history edited Timothy Foo CC BY-SA 3.0
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Oct 28, 2011 at 6:39 history edited Timothy Foo CC BY-SA 3.0
deleted 26 characters in body; added 8 characters in body; added 12 characters in body
Oct 28, 2011 at 6:33 history asked Timothy Foo CC BY-SA 3.0