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Oct 27, 2011 at 21:35 comment added user6976 a-T-menability is a strong negation of property (T). The class of a-T-memable groups contains all amenable groups. Another approximation of amenability is G.Yu's property A. It is not known whether $F$ satisfies property A. That question seems to be as hard as amenability. Free groups and even all hyperbolic groups satisfy A.
Oct 27, 2011 at 21:26 comment added Valerio Capraro Well, also free groups are a-T-menable... this is, by the way and little off-topic, one of the reasons why I don't understand very well in which sense a-T-menability is considered close to amenability. Anyway, many thanks for the information.
Oct 27, 2011 at 20:17 comment added user6976 You can deduce that $F$ is a-T-menable, for example. That is the closest to amenability known property of $F$.
Oct 27, 2011 at 20:13 vote accept Valerio Capraro
Oct 27, 2011 at 20:12 comment added Valerio Capraro OK, thank you. What kind of information one can get in this other way; namely viewing $F$ as a fundamental group of an infinite dimensional cubical complex with $CAT(0)$ universal cover?
Oct 27, 2011 at 19:59 comment added user6976 About 2), the construction of Kuzmin is explicit. About 3): there were no attempts (successful or not) because the idea does not seem to be fruitful: there seems to be no info you can get from the manifold that you cannot obtain just by looking at the very simple defining relations of $F$. One can get more information viewing $F$ as a fundamental group of an infinite dimensional cubical complex with CAT(0) universal cover.
Oct 27, 2011 at 19:51 history edited Valerio Capraro CC BY-SA 3.0
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Oct 27, 2011 at 19:41 history edited Valerio Capraro CC BY-SA 3.0
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Oct 27, 2011 at 19:32 comment added Valerio Capraro I was just thinking, while having a shower, to modify the question!
Oct 27, 2011 at 19:31 comment added Mariano Suárez-Álvarez @Valerio: it usually works better if you ask the subquestions explicitly :)
Oct 27, 2011 at 19:28 answer added user6976 timeline score: 8
Oct 27, 2011 at 19:18 comment added Valerio Capraro Indeed my question contains many (maybe trivial) subquestions: 1) Does a 4-manifold with amenable fundamental group have any characterizing properties? 2) Is there an explicit way to construct a 4-manifold whose fundamental group is the Thompson group?
Oct 27, 2011 at 18:49 comment added Andy Putman Since every group is the fundamental group of a $4$-manifold but most groups are not amenable, I can't see how this would buy you anything. One would need a $4$-manifold with some kind of extra structure that not all $4$-manifolds have, and I don't see how to do that with Thompson's group.
Oct 27, 2011 at 18:24 history asked Valerio Capraro CC BY-SA 3.0