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Dec 8, 2009 at 10:25 vote accept Hideyuki Kabayakawa
Dec 6, 2009 at 16:15 comment added Hideyuki Kabayakawa A module M is said reflexive iff (R:(R:M))=M. Here (R:M)=Hom(M,R). For example, projective modules are reflexives. When R is noetherian integrally closed domain, all prime ideals with height 1 are reflexives modules. It is known (Bourbaki, chapter 7) all reflexives finitely generated modules are the intersection of two free modules. I´m trying to make a picture of that. Vector bundle is the corresponding topological concept to projective finitely generated module and that´s the reason of my question.
Dec 6, 2009 at 14:41 comment added Charles Siegel I might be able to help more if you could tell me what a reflexive module is? I did a quick google search and couldn't find the definition, and I'm not familiar with it (though might have run across it by a different name, or as an unnamed property, perhaps)
Dec 6, 2009 at 2:33 answer added Charles Siegel timeline score: 2
Dec 6, 2009 at 0:50 history edited Ilya Nikokoshev
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Dec 6, 2009 at 0:49 answer added Ilya Nikokoshev timeline score: 1
Dec 6, 2009 at 0:42 history edited Hideyuki Kabayakawa CC BY-SA 2.5
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Dec 6, 2009 at 0:36 comment added Hideyuki Kabayakawa Literally intersection: Suppose two sub-bundles of a bundle over a topological space X. We can do the intersection of their vector fibers in each point of base space and collect this intersection vector fibers along the base space. Then we can give it a topology, restriction of the bigger vector bundle. What´s about of this "submodule of sections"? Is it another vector bundle? Has another interesting structure? –
Dec 6, 2009 at 0:25 answer added Hailong Dao timeline score: 4
Dec 5, 2009 at 23:59 comment added Charles Siegel What do you mean the "intersection" of two vector bundles?
Dec 5, 2009 at 23:48 history asked Hideyuki Kabayakawa CC BY-SA 2.5