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Oct 21, 2011 at 4:36 history edited Allen Knutson CC BY-SA 3.0
H is torus -> H contains torus
Oct 21, 2011 at 1:36 comment added algori Dear Faisal -- you are right about the connectedness of $H$. E.g., $S^2=SO(3)/SO(2)$ and $\mathbb{P}^2(\mathbb{R})=SO(3)/\pm SO(2)$.
Oct 21, 2011 at 0:35 comment added Faisal Also, it might be helpful to say in words that the cohomology of $C^\ast(g,h,A)$ is precisely the relative Lie algebra cohomology $H^\ast(g,h,A)$.
Oct 21, 2011 at 0:33 comment added Faisal Hi algori, I hope you don't mind, but I edited your answer to fix a few typos. I also added the (necessary) assumption that both $H$ and $G$ be connected.
Oct 21, 2011 at 0:30 history edited Faisal CC BY-SA 3.0
added 15 characters in body
Oct 20, 2011 at 23:59 history answered algori CC BY-SA 3.0