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Oct 28, 2012 at 14:19 vote accept CommunityBot
Oct 19, 2011 at 21:36 comment added Marcel Bischoff I refer to the domain. Ok the problem is that the word "Hermitian operator" is used differently in the literature. For bounded operators there are no problems at all. But normally self-adjoint is stronger then hermitian or symmetric.
Oct 19, 2011 at 21:19 comment added MTS What do you mean by "the difference between Hermitian and self-adjoint operators"? Are you referring to boundedness? Because for bounded operators I thought the terms were completely interchangeable.
Oct 19, 2011 at 21:15 history answered Marcel Bischoff CC BY-SA 3.0