Skip to main content
4 events
when toggle format what by license comment
Aug 23, 2022 at 10:45 comment added ghc1997 Thanks @Ycor, on a related note, when $G$ is residually finite, but $N$ is not f.g, may I ask if you know any necessary condition that $N$ needs to have (other than being residually finite)?
Aug 23, 2022 at 10:31 comment added YCor @ghc1997 To weaken the condition that $N$ is fg: if $N$ is RF and has finitely many subgroup of each given finite index (automatic if $N$ is fg), then it is true that $G$ is RF. An even weaker condition is that the $\mathbf{Z}$-action on the set of normal subgroups of finite index of $N$ has no infinite orbit. (Still, this is not yet necessary, as the lampighter group $C_2\wr \mathbf{Z}$ witnesses.)
Aug 23, 2022 at 10:15 comment added ghc1997 Hi Yves, in the case where $G$ is residually finite, but $N$ is not f.g. Are there any results that tell us what other properties $N$ need to have? As you pointed out, $N$ being residually finite is a necessary but not sufficient condition.
Oct 17, 2011 at 17:37 history answered YCor CC BY-SA 3.0