Timeline for Countability of eigenvalues of a linear operator
Current License: CC BY-SA 3.0
6 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Sep 29, 2013 at 17:11 | comment | added | Matthias Ludewig | The example shows that you are wrong, user36539. It is an operator with uncountably many ACTUAL eigenvectors to differnt eigenvalues in the SAME Hilbert Space! | |
| Sep 28, 2013 at 10:20 | comment | added | user36539 | in a separable HS the basis is countable. you probably mean a continuum of "eigenvectors" which belong to a space wider than HS (Dirac) | |
| Sep 27, 2013 at 20:57 | comment | added | Matthew Daws | Separable = countable dense subset... | |
| Sep 27, 2013 at 18:16 | comment | added | user36539 | How this can be possible if we work in a separate Hilbert space ? Yes we may have a continuum of spectral values but certainly not a continuum of eigenvectors ! | |
| Oct 15, 2011 at 21:26 | vote | accept | Matthias Ludewig | ||
| Oct 15, 2011 at 19:28 | history | answered | Matthew Daws | CC BY-SA 3.0 |