Timeline for Countability of eigenvalues of a linear operator
Current License: CC BY-SA 3.0
8 events
| when toggle format | what | by | license | comment | |
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| Sep 27, 2013 at 18:18 | answer | added | user36539 | timeline score: -2 | |
| Oct 15, 2011 at 23:14 | comment | added | Faisal | Compact operators have countably many eigenvalues. If you think about why normal operators do too, you'll see that it's essentially because eigenvectors corresponding to different eigenvalues are orthogonal. So any operator satisfying this condition will have countably many eigenvalues. For example subnormal operators--or more generally, hyponormal operators--fit the bill. | |
| Oct 15, 2011 at 21:26 | vote | accept | Matthias Ludewig | ||
| Oct 15, 2011 at 21:26 | vote | accept | Matthias Ludewig | ||
| Oct 15, 2011 at 21:26 | |||||
| Oct 15, 2011 at 21:26 | comment | added | Matthias Ludewig | So are there any other natural conditions that ensure that the number of eigenvalues is countable apart from normality of the operator? | |
| Oct 15, 2011 at 19:30 | answer | added | Faisal | timeline score: 9 | |
| Oct 15, 2011 at 19:28 | answer | added | Matthew Daws | timeline score: 13 | |
| Oct 15, 2011 at 19:16 | history | asked | Matthias Ludewig | CC BY-SA 3.0 |