Timeline for determinant of the table of characters
Current License: CC BY-SA 3.0
14 events
| when toggle format | what | by | license | comment | |
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| Oct 14, 2011 at 20:10 | history | edited | François G. Dorais |
edited tags
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| Oct 14, 2011 at 12:48 | history | edited | Denis Serre | CC BY-SA 3.0 |
deleted 514 characters in body
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| Oct 14, 2011 at 5:34 | answer | added | Denis Serre | timeline score: 9 | |
| Oct 14, 2011 at 5:27 | comment | added | Denis Serre | @Dick. You mean, as elements of a cyclotomic ring? | |
| Oct 14, 2011 at 0:22 | comment | added | Richard Stanley | One can also ask about determinants of submatrices of the character table, a much more subtle question. See front.math.ucdavis.edu/1110.0818. | |
| Oct 13, 2011 at 21:53 | comment | added | S. Carnahan♦ | I think you should post the answer as an answer. | |
| Oct 13, 2011 at 20:14 | comment | added | Noam D. Elkies | @Denis thanks, but you still need a $\pm$ sign (also for the general formula, since the nice argument you give computes only the absolute value $|\Delta|$, not $\Delta$ itself). | |
| Oct 13, 2011 at 20:12 | answer | added | Igor Rivin | timeline score: 7 | |
| Oct 13, 2011 at 20:09 | history | edited | Denis Serre | CC BY-SA 3.0 |
added 408 characters in body; added 100 characters in body
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| Oct 13, 2011 at 20:07 | answer | added | Faisal | timeline score: 13 | |
| Oct 13, 2011 at 20:06 | comment | added | Denis Serre | @Noam. Right. I edit. | |
| Oct 13, 2011 at 20:04 | comment | added | Noam D. Elkies | If $G={\bf Z}/n{\bf Z}$ then $\Delta$ is the square of a Vandermonde determinant, and can be computed in closed form, but the answer is not $n^2$ but $\pm n^n$, with the sign depending on $n \bmod 4$ if I did this right. | |
| Oct 13, 2011 at 19:41 | answer | added | Benjamin Steinberg | timeline score: 3 | |
| Oct 13, 2011 at 19:34 | history | asked | Denis Serre | CC BY-SA 3.0 |