Timeline for Proofs of parity results via the Handshaking lemma
Current License: CC BY-SA 4.0
13 events
when toggle format | what | by | license | comment | |
---|---|---|---|---|---|
Dec 28, 2022 at 14:49 | comment | added | Fedor Petrov | @GerryMyerson that's an example of what is mentioned in the pre-last paragraph. But a more involved group theory result would be highly appreciated. | |
Dec 28, 2022 at 14:37 | comment | added | Gerry Myerson | Maybe this example is too simple to post as an answer: Given a group of even order, form the graph with an edge joining each element to its inverse. The identity element is unpaired, so there must be at least one more unpaired element; thus, the group must have an element of order two. | |
Jun 14, 2021 at 7:52 | history | edited | Fedor Petrov | CC BY-SA 4.0 |
deleted 21 characters in body
|
Mar 1, 2019 at 18:33 | history | edited | darij grinberg | CC BY-SA 4.0 |
empty graphs work fine here
|
Mar 1, 2019 at 17:50 | history | edited | Fedor Petrov | CC BY-SA 4.0 |
added 48 characters in body
|
Jan 14, 2018 at 13:16 | history | made wiki | Post Made Community Wiki by Todd Trimble | ||
Jan 14, 2018 at 2:35 | history | edited | YCor |
edited tags
|
|
Oct 12, 2011 at 16:04 | answer | added | Timothy Chow | timeline score: 8 | |
Oct 12, 2011 at 12:34 | answer | added | Tony Huynh | timeline score: 4 | |
Oct 12, 2011 at 10:40 | history | edited | Fedor Petrov | CC BY-SA 3.0 |
edited title
|
Oct 12, 2011 at 10:11 | answer | added | Gjergji Zaimi | timeline score: 11 | |
Oct 12, 2011 at 8:53 | history | edited | Fedor Petrov |
edited tags
|
|
Oct 12, 2011 at 8:33 | history | asked | Fedor Petrov | CC BY-SA 3.0 |