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Oct 11, 2011 at 22:43 comment added algori .. apart from the zero one.
Oct 11, 2011 at 22:32 comment added algori Joe -- take $G=\mathbb{Q}/\mathbb{Z}$. Since $G\otimes_{\mathbb{Z}}G=0$, there are no ring structures on $G$ at all.
Oct 11, 2011 at 21:24 history closed Dan Petersen
Gjergji Zaimi
HJRW
Felipe Voloch
Zev Chonoles
not a real question
Oct 11, 2011 at 20:23 comment added Joe Silverman This question is sufficiently vague as to have little content. First when you say $E$ is an elliptic curve and you want to make $E$ into a ring, you're presumably talking about the points of $E$. So you must specify a field. Second, if you simply want a ring "in a non-trivial way", the answer doesn't seem interesting. (Generally, if $G$ is an abstract abelian group, can one put a non-trivial ring structure on it?) Maybe the right question is: Can we find an algebraic map $E\times E\to E$ that we'll call multiplication and that, with +, satisfies the ring axioms. The answer to that is no.
Oct 11, 2011 at 20:17 comment added user2035 Not in a useful way, no. Depending on your precise setting (ground field), sometimes not at all.
Oct 11, 2011 at 20:09 history asked Aleks Vlasev CC BY-SA 3.0