Timeline for Example for Busemann function is not an exhaustion when Ricci $\ge 0$
Current License: CC BY-SA 3.0
16 events
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| Oct 26, 2011 at 22:40 | answer | added | Bo_Y | timeline score: 4 | |
| Oct 5, 2011 at 22:00 | answer | added | Vitali Kapovitch | timeline score: 4 | |
| Oct 5, 2011 at 21:38 | history | edited | user16750 | CC BY-SA 3.0 |
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| Oct 5, 2011 at 21:30 | history | edited | user16750 | CC BY-SA 3.0 |
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| Oct 5, 2011 at 20:57 | comment | added | Igor Rivin | I feel exhaustion setting in... | |
| Oct 5, 2011 at 19:49 | comment | added | Deane Yang | And I'm getting confused by the definition of the Busemann function in terms of the "usual Busemann function". Could you give a complete definition of $b(x)$ from scratch? | |
| Oct 5, 2011 at 19:40 | history | edited | user16750 | CC BY-SA 3.0 |
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| Oct 5, 2011 at 19:34 | comment | added | Deane Yang | Thanks but could you also define what an "exhaustion function" is? | |
| Oct 5, 2011 at 19:23 | history | edited | user16750 | CC BY-SA 3.0 |
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| Oct 5, 2011 at 19:22 | comment | added | user16750 | Sorry for any misleading due to my typo and not describe the question clearly. The Buesemann function is $b(x)=\sup b_{\gamma}(x)$ where the sup is taken over all rays and $b_{\gamma}$ is the usual busemann function. | |
| Oct 5, 2011 at 19:19 | comment | added | Sergei Ivanov | Ok, what is "exhaustion"? If this means a function whose sublevels are compact (the only definition I could find), then your first claim is false. For example, consider a Euclidean space. | |
| Oct 5, 2011 at 19:19 | comment | added | Deane Yang | But could you define what an "exhaustion function" is? | |
| Oct 5, 2011 at 19:01 | comment | added | user16750 | sorry, should be exhaustion. | |
| Oct 5, 2011 at 19:00 | history | edited | user16750 | CC BY-SA 3.0 |
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| Oct 5, 2011 at 18:56 | comment | added | Sergei Ivanov | What is "exaustion"? | |
| Oct 5, 2011 at 18:41 | history | asked | user16750 | CC BY-SA 3.0 |