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Oct 10, 2011 at 17:22 answer added David E Speyer timeline score: 3
Oct 10, 2011 at 7:46 answer added Xandi Tuni timeline score: 5
Oct 5, 2011 at 16:54 comment added Christopher A. Wong In case anybody was wondering, I basically misread the problem, so my above comments don't make much sense. It is true, however, that it may be impossible to define a logarithm consistently on $f(U)$; but that's not what the question is asking.
Oct 5, 2011 at 12:56 history edited BS. CC BY-SA 3.0
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Oct 5, 2011 at 8:58 answer added Denis Serre timeline score: 1
Oct 5, 2011 at 8:52 comment added Christopher A. Wong Yes, but we need define a logarithm that is consistent across all matrices in $f(U)$.
Oct 5, 2011 at 8:48 comment added Suvrit Every nonsingular matrix $A$ has a logarithm that is a polynomial in $A$...
Oct 5, 2011 at 8:35 comment added Christopher A. Wong I think this depends on the choice of $f$. We need to define a branch of logarithm that does not cross the spectrum of any matrix in the image of $f$. I'm not sure that's always guaranteed to be possible.
Oct 5, 2011 at 7:53 history asked Xandi Tuni CC BY-SA 3.0