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Timeline for properness of stack

Current License: CC BY-SA 3.0

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Oct 5, 2011 at 10:25 comment added S. Carnahan I think $A = B = \mathbb{A}^1$ is a counterexample.
Oct 5, 2011 at 10:20 comment added uuuuuuuuuuuu @knob call this subgroup $G$ then $B$ is the stack with the same objects of $A$ but with $Hom_B(x,y):=Hom_A(x,y)/y^{*} G$ where the action is the composition action @Keerthi Madapusi Pera I only have these hypoteses and $A$ is not proper
Oct 4, 2011 at 22:57 comment added Keerthi Madapusi Is $A$ assumed to be proper?
Oct 4, 2011 at 22:38 comment added Yosemite Sam out of curiosity: what do you mean by rigidifying?
Oct 4, 2011 at 17:58 history asked uuuuuuuuuuuu CC BY-SA 3.0