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Oct 4, 2011 at 18:21 comment added Legend Great! Thank you once again for your time.
Oct 4, 2011 at 18:21 vote accept Legend
Oct 4, 2011 at 6:22 comment added Robert Israel Yes, that looks good to me.
Oct 4, 2011 at 0:19 comment added Legend @Robert Israel: +1 Thank you for your comments. So from what I understand, I posted another snippet of the code. Could you please tell me if I am on the right page? Basically, instead of the all-or-none scenario, what I am now doing is calculating the probability for each neighbor within a node's vicinity.
Oct 4, 2011 at 0:07 history answered Robert Israel CC BY-SA 3.0