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Timeline for Clifford algebra as an adjunction?

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Dec 3, 2009 at 21:36 comment added Mariano Suárez-Álvarez By the way, the fact that a left adjoint preserves coproducts of course is true, and one can construct coproducts in the category of Z_2 graded algebras (imitating the construction of the free product of groups) so you can make something out of this argument.
Dec 3, 2009 at 19:44 comment added José Figueroa-O'Farrill Yes, but there are useful ways of being wrong :)
Dec 3, 2009 at 18:57 history edited Alicia Garcia-Raboso CC BY-SA 2.5
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Dec 3, 2009 at 18:55 comment added Mariano Suárez-Álvarez In any case, the Clifford algebra of an orthogonal direct sum of quadratic spaces is isomorphic to the twisted tensor product of the corresponding tensor algebras: this is the "super" tensor product, the one which introduces signs by the parity graduation of the Clifford algebras.
Dec 3, 2009 at 18:54 comment added Alicia Garcia-Raboso My bad: Clifford algebras are Z_2-graded, and hence the coproduct is the Z_2-graded tensor product. Proposition 1.5 on page 11 of Lawson and Michelsohn's "Spin Geometry" asserts that Cl indeed preserves coproducts.
Dec 3, 2009 at 18:53 comment added José Figueroa-O'Farrill Curiously, since Clifford algebras are $\mathbb{Z}_2$-graded, if you were to take the $\mathbb{Z}_2$-graded tensor product in your first displayed equation, then this would be a true statement. This perhaps suggestst that I have to consider the category of $\mathbb{Z}_2$-graded associative algebras.
Dec 3, 2009 at 18:42 comment added Mariano Suárez-Álvarez The coproduct in the category of associative algebras is not the tensor product: two maps $f:A\to C$ and $f:B\to C$ give a map $A\otimes B\to C$ only if the images of $f$ and of $g$ commute.
Dec 3, 2009 at 18:27 history answered Alicia Garcia-Raboso CC BY-SA 2.5