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Oct 4, 2011 at 17:40 comment added user6976 @Mark: The proof should go like this. First embed your Abelian group into a full group. Note that the full group can be assumed locally cyclic too. Then use the description of Abelian full groups.
Oct 4, 2011 at 17:20 comment added Mark Wildon Many thanks for these references. For torsion-free groups the result is mentioned on page 109 of Fuchs "Infinite Abelian Groups", Volume II. I cannot find the torsion case in Fuchs in any explicit form. Marshall Hall's "Theory of Groups" page 340 has "The additive group of rationals $R_+$ is a locally cyclic group which is aperiodic, and the group $R_+$ modulo $1$ is a periodic locally cyclic group. It is not too difficult to show that a locally cyclic group is a subgroup of one of these two groups." (No proof is given.)
Oct 2, 2011 at 16:54 vote accept Mark Wildon
Sep 30, 2011 at 17:07 history edited user6976 CC BY-SA 3.0
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Sep 30, 2011 at 13:44 history answered user6976 CC BY-SA 3.0