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Jul 21, 2022 at 17:40 comment added jjcale $\frac{\Gamma(1/10) \Gamma(9/10)}{\Gamma(3/10) \Gamma(7/10)} = \frac{sin(3\pi / 10)}{sin(\pi / 10)} = \frac{3+\sqrt{5}}{2}$
Nov 19, 2021 at 3:08 comment added David Roberts Problems and Solutions, The American Mathematical Monthly, 117:9 (2010) pp 834-843, doi.org/10.4169/000298910x521724
Aug 20, 2014 at 15:59 comment added Gerald Edgar Amer. Math. Monthly, November 2010, page 842
Dec 3, 2009 at 13:16 history answered Gerald Edgar CC BY-SA 2.5